Question

Figure 19 illustrates a circuit containing three capacitors connected in series. The three capacitor values are 0.5 µF, 0.2 µF, and 1.0 µF. Use the formula to calculate the total capacitance of this circuit.

Options:

Option 1: 0.7 µF

Option 2: 0.3 µF

Option 3: 1.7 µF

Option 4: 1.0 µF

Answer 1

After performing the series capacitance calculation, the total capacitance for the given capacitors in series is 0.125 µF, which does not match any of the provided options. This suggests there could be a mistake in the question or the options given.

The correct option is not given.

Step-by-step explanation:

To calculate the total capacitance of capacitors connected in series, we use the reciprocal formula:

1. 1/Ctotal = 1/C1 + 1/C2 + 1/C3

For the given capacitors:

1. 1/Ctotal = 1/0.5 µF + 1/0.2 µF + 1/1.0 µF
2. 1/Ctotal = 2 µF-1 + 5 µF-1 + 1 µF-1
3. 1/Ctotal = 8 µF-1
4. Ctotal = 1/8 µF = 0.125 µF

Therefore, the total capacitance of the three capacitors in series is 0.125 µF.

However, this option does not appear in the provided options. It seems there might be a mistake since the correct answer should be included in the options.

You should double-check your calculations or inputs to ensure the values and units are correct.

The correct option is not given.