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find two consecutive even integers so that 18 times the smaller number is 2 more than 17 times that larger number

asked
User Feradz
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8.3k points

1 Answer

5 votes

Final answer:

To find two consecutive even integers, we can set up an equation using the given information. By simplifying and solving the equation, we find that the two consecutive even integers are 38 and 40.

Step-by-step explanation:

To find two consecutive even integers, we can represent the smaller number as x, and the larger number as x + 2.

The problem states that 18 times the smaller number is 2 more than 17 times the larger number.

So, we can set up the equation: 18x = 17(x + 2) + 2.

Simplifying the equation, we get 18x = 17x + 36 + 2.

Combining like terms, we have x = 38.

Therefore, the two consecutive even integers are 38 and 40.

answered
User Procatmer
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7.9k points

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