Question

Which sets does not contains the value? (2+6i)(2-6i)-50

Answer 1

To find the value of (2+6i)(2-6i)-50, you multiply the complex number by its conjugate and subtract 50, resulting in the real number -10.

Step-by-step explanation:

The question involves computing the value of a complex number expression and then subtracting 50 from it. First, we need to perform the multiplication (2+6i)(2-6i), which is a product of a complex number and its conjugate. This results in a real number:

• (2+6i)(2-6i) = 2² - (6i)² = 4 - (-36) = 4 + 36 = 40.

After finding the product, we subtract 50:

• 40 - 50 = -10.

Therefore, the given expression (2+6i)(2-6i) - 50 equals -10, which is a real number and not a complex number.