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In the following exercises, find the Taylor polynomials of degree 2 to approximate the given function centered at the given point.

(a) ( f(x) )

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Final answer:

For the function
\( f(x) = e^x \) and center \( c = 0 \), the Taylor polynomial of degree 2 is
\( P_2(x) = 1 + x + (1)/(2)x^2 \), calculated by evaluating function values, derivatives, and applying the Taylor polynomial formula.

Step-by-step explanation:

To find the Taylor polynomial of degree 2 for a given function centered at a specific point, we'll use the formula for the Taylor polynomial:


\[ P_n(x) = f(c) + f'(c)(x - c) + (f''(c))/(2!)(x - c)^2 \]

where
\( f(c) \) is the function value at the center,
\( f'(c) \) is the first derivative at the center,
\( f''(c) \) is the second derivative at the center, and so on.

Let's assume we have a function
\( f(x) \) and we want to find the Taylor polynomial of degree 2 centered at
\( c \).

Here's a step-by-step guide on how to find the Taylor polynomial:

1. Find the function value
\( f(c) \) at the center.

2. Find the first derivative
\( f'(x) \).

3. Evaluate
\( f'(x) \) at the center
\( c \) to find
\( f'(c) \).

4. Find the second derivative
\( f''(x) \).

5. Evaluate
\( f''(x) \) at the center
\( c \) to find
\( f''(c) \).

6. Substitute these values into the formula to obtain the Taylor polynomial of degree 2.

Let's go through a specific example. Suppose we have the function
\( f(x) = e^x \) and we want the Taylor polynomial of degree 2 centered at
\( c = 0 \).

1. Find
\( f(0) \):


\[ f(0) = e^0 = 1 \]

2. Find
\( f'(x) \):


\[ f'(x) = e^x \]

3. Evaluate
\( f'(x) \) at \( c = 0 \) to find \( f'(0) \):


\[ f'(0) = e^0 = 1 \]

4. Find
\( f''(x) \):


\[ f''(x) = e^x \]

5. Evaluate
\( f''(x) \) at \( c = 0 \) to find \( f''(0) \):


\[ f''(0) = e^0 = 1 \]

6. Substitute these values into the Taylor polynomial formula:


\[ P_2(x) = 1 + 1(x - 0) + (1)/(2!)(x - 0)^2 \]


\[ P_2(x) = 1 + x + (1)/(2)x^2 \]

So, the Taylor polynomial of degree 2 for
\( f(x) = e^x \) centered at
\( c = 0 \) is \( P_2(x) = 1 + x + (1)/(2)x^2 \).

answered
User Gene Myers
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8.3k points
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