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(y-3)²+(x-4)²=5 What is the center of the circle?

1 Answer

5 votes

Final answer:

The center of the circle represented by the equation (y-3)²+(x-4)²=5 is at the point (4, 3).

Step-by-step explanation:

The equation (y-3)²+(x-4)²=5 represents a circle in the coordinate system. To find the center of the circle, we can compare the equation to the standard form of a circle's equation, which is (y-k)²+(x-h)²=r², where (h, k) is the center and r is the radius. Using this comparison, we can see that the center of the circle is at the point (4, 3).

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User Nmvictor
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