Question

F total pressure in a gas mixture is 400 mmHg and the oxygen content is 40%, what is the partial pressure of oxygen?

A. 400 mmHg
B. 160 mmHg
C. 100 mmHg
D. 80 mmHg

Answer 1

The partial pressure of oxygen in a mixture with a total pressure of 400 mmHg and 40% oxygen content is 160 mmHg (B).

Step-by-step explanation:

If the total pressure in a gas mixture is 400 mmHg and the oxygen content is 40%, to find the partial pressure of oxygen (O₂), we can use the formula:

P = (Patm) X (% content in mixture).

Here, the atmospheric pressure (Patm) is the total pressure of the gas mixture, which is given as 400 mmHg. To calculate the partial pressure of oxygen, we use its percent content in the mixture, which is 40% or 0.40 when converted to decimal. So, the partial pressure of oxygen is calculated as follows:

Po₂ = (400 mmHg) X (0.40) = 160 mmHg.

Therefore, the correct answer is B. 160 mmHg.