Question

Write the balanced equation and determine what volume of 0.2500m cobalt (iii) sulfate is required to react completely with 25.00ml of 0.0315m calcium hydroxide. co2(so4)3 (aq) ca(oh)2 (aq) →

Answer 1

The balanced equation for the reaction is Co2(SO4)3 (aq) + 3Ca(OH)2 (aq) → Co(OH)3 (s) + 3CaSO4 (aq). The volume of 0.2500 M cobalt (III) sulfate required to react completely with 25.00 mL of 0.0315 M calcium hydroxide is 3.15 mL.

Step-by-step explanation:

The balanced equation for the reaction between cobalt (III) sulfate and calcium hydroxide is:

Co2(SO4)3 (aq) + 3Ca(OH)2 (aq) → Co(OH)3 (s) + 3CaSO4 (aq)

To determine the volume of 0.2500 M cobalt (III) sulfate required to react completely with 25.00 mL of 0.0315 M calcium hydroxide, we can use the equation:

(0.0315 M) x (25.00 mL) = (0.2500 M) x (volume of cobalt (III) sulfate)

Solving for the volume of cobalt (III) sulfate, we get:

volume of cobalt (III) sulfate = (0.0315 M x 25.00 mL) / 0.2500 M = 3.15 mL