Question

The position of a moving object is given as a = (t² + 3t+2)m, where tis time in second. The acceleration of the object at t = 1s will be​

Answer 1

The acceleration of an object with a position function a = (t² + 3t + 2)m at t = 1s is found by taking the second derivative of the position function, resulting in a constant acceleration of 2 m/s².

Step-by-step explanation:

To find the acceleration of the object at t = 1s given the position function a = (t² + 3t + 2)m, we need to differentiate the position function to obtain the velocity function, and then differentiate the velocity function to obtain the acceleration function.

First derivative (velocity as a function of time):
v(t) = d(a)/dt = 2t + 3

Second derivative (acceleration as a function of time):
a(t) = d(v)/dt = 2

Therefore, the acceleration at t = 1s is 2 m/s², which is constant for any value of t.