Question

The sum of twice a number and seven is less than 27 right and solve an inequality statement to figure out the constraints on this number

Answer 1

To solve the inequality, subtract 7 from both sides and then divide by 2 to isolate the variable x. The constraints on the number x are that it must be less than 10.

Step-by-step explanation:

To solve the inequality, let's define the unknown number as 'x'. The sum of twice x and seven can be expressed as 2x + 7. The inequality states that this sum is less than 27, so we can write it as 2x + 7 < 27.

To solve the inequality, we'll start by subtracting 7 from both sides: 2x + 7 - 7 < 27 - 7; this simplifies to 2x < 20. Then, we divide both sides by 2 to isolate the variable x: 2x/2 < 20/2, which simplifies to x < 10.

Therefore, the constraints on the number 'x' are that it must be less than 10.