Final answer:
After setting up two equations based on the given problem, we find that the smaller number is 4 and the larger number is 7, responding to the question with option A) Larger number: 7, Smaller number: 4.
Step-by-step explanation:
To solve the problem where the larger of two numbers is 1 less than twice the smaller number, let's designate the smaller number as x and the larger number as y. According to the problem, y = 2x - 1. Next, the statement that 5 times the larger is equal to 3 times the smaller increased by 23 translates to 5y = 3x + 23.
Now, let's substitute the first equation into the second:
- 5(2x - 1) = 3x + 23
- 10x - 5 = 3x + 23
- 10x - 3x = 23 + 5
- 7x = 28
- x = 4
Now that we know x, the smaller number, is 4, we can find y by substituting x back into the equation y = 2x - 1:
- y = 2(4) - 1
- y = 8 - 1
- y = 7
The larger number is 7 and the smaller number is 4. Therefore, the answer is option A) Larger number: 7, Smaller number: 4.