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Given z is a standard normal random variable. what is pr(z < -1.41)?

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User Newleaf
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1 Answer

6 votes

Final answer:

The probability of z being less than -1.41 is 0.3446.

Step-by-step explanation:

The z-table shows that the area to the left of z is 0.6554. Subtracting this area from 1 gives 0.3446. Since we need to find pr(z < -1.41), which means finding the area to the left of -1.41, we can conclude that pr(z < -1.41) = 0.3446.

answered
User Nurul Huda
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8.2k points

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