asked 230k views
14 votes
Fireworks are set off from a hill 80 feet above the Mississippi. The outer

shells will fall after exploding at its maximum height. The firework's height
about the surface of the river is given by the function h(t) = -16t^2 + 64t +
80. What is the height of the rocket after 1.5 seconds?

1 Answer

6 votes

Answer:

752 ft

Explanation:

Assuming t represents time, and the time we are trying to find is how high the rockets go after 1.5 seconds, we must take the equation and put 1.5 in wherever t occurs, this looks like:

-16(1.5)²+64(1.5)+80

solving this, we get:

-24²+96+80

576+96+80

752

answered
User AndrewR
by
7.8k points
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