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A parallel-plate air capacitor has a capacitance of 920 pf. The charge on each plate is 3.90 μc. Calculate the potential difference existing between the plates of the capacitor.

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User IsADon
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1 Answer

6 votes

Final answer:

To calculate the potential difference between the plates of a parallel-plate capacitor, use the formula V = Q / C, where V is the potential difference, Q is the charge on each plate, and C is the capacitance.

Step-by-step explanation:

The potential difference between the plates of a parallel-plate capacitor can be calculated using the formula:

V = Q / C

Where V is the potential difference (in volts), Q is the charge on each plate (in coulombs), and C is the capacitance (in farads).

In this case, the charge on each plate is 3.90 μC and the capacitance is 920 pF. Converting the capacitance to farads gives:

C = 920 x 10^(-12) F

Substituting these values into the formula, the potential difference is:

V = (3.90 x 10^(-6) C) / (920 x 10^(-12) F)

answered
User Aman Gupta
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9.7k points
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