Final answer:
The student is asking how many moles of FeO will be produced from 7.4g of O₂ based on the reaction 4Fe + 3O₂ → 2Fe₂O₃, there is an error as FeO and Fe₂O₃ are not the same. The correct calculation shows that 7.4g of O₂ will produce 0.154 mol of Fe₂O₃ (iron (III) oxide).
Step-by-step explanation:
Given the reaction 4Fe + 3O₂ → 2Fe₂O₃, the student is asking how many moles of FeO will be produced from 7.4g of O₂. However, there is a mistake in the question as FeO and Fe₂O₃ (iron (III) oxide) are two different compounds. Based on the given reaction, iron (III) oxide (Fe₂O₃) is produced, not FeO. To answer the question as intended, first, we need to convert the mass of oxygen to moles using the molar mass of O₂, which is approximately 32.00 g/mol.
7.4 g O₂ × (1 mol O₂ / 32.00 g O₂) = 0.231 mol O₂. The balanced equation indicates that 3 moles of O₂ produce 2 moles of Fe₂O₃. Using the stoichiometric mole ratio, (2 mol Fe₂O₃ / 3 mol O₂) we find that 0.231 mol O₂ will produce (0.231 mol O₂) × (2 mol Fe₂O₃ / 3 mol O₂) = 0.154 mol Fe₂O₃.