Final answer:
To calculate the amount of copper that must have been added to 1000 mL of water to produce the given electrode potential, we can use the equation E = E° - (0.0592/n)log[Copper(II)]. By solving this equation, we can find the concentration of Copper(II), which will allow us to calculate the amount of copper added to the water.
Step-by-step explanation:
In this question, we are given that a half-cell produced by dissolving copper in water produces an electrode potential of 0.32 V.
To calculate the amount of copper that must have been added to 1000 mL of water to produce this potential, we need to use the equation relating electrode potential to concentration:
E = E° - (0.0592/n)log[Copper(II)].
By substituting the known values into this equation, we can solve for the concentration of Copper(II), which will allow us to calculate the amount of copper added to the water.