asked 136k views
15 votes
If the kinetic energy of the 40kg box is 784 J, what is the velocity before it strikes the ground?

asked
User Rigdonmr
by
8.8k points

1 Answer

11 votes

Answer:

Step-by-step explanation:


KE=(1)/(2)mv^2


784=(1)/(2)(40)v^2


784=20v^2


39.2=v^2


v=6.26m/s

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