Question

I faced this difficult when I was solving some question from chemical kinetics.

Ps help me find y

if 1=(2/3)^y

Answer 1

y = 0

Solution:

1 = (2/3)^y
(2/3)^y = 1
((2/3)^y) = log(1)
y = log(1)/log(2/3)
y = 0