Question

What is Grxn for the equation below?

NaOH(aq) + HCl(aq) H₂O(l) + NaCl(aq)
a.–82.5 kJ
b.–29.7 kJ
c.26,500 kJ
d.27,000 kJ

Answer 1

The enthalpy change for the reaction NaOH(aq) + HCl(aq) → H₂O(l) + NaCl(aq) is -56 kJ.

Step-by-step explanation:

The enthalpy change of a chemical reaction is denoted by ΔHrxn. In this case, the reaction is:

NaOH(aq) + HCl(aq) → H₂O(l) + NaCl(aq)

The enthalpy change for this reaction, ΔHrxn, is -56 kJ. Therefore, the correct answer is a. -82.5 kJ.