Question

The equation Y-5 = 6(x+1) is written in point-slope form. What is the equation written in slope-intercept form?

A) y = 6x + 11
B) y = 6x - 1
C) y = 6x - 4
D) y = 6x + 6

Answer 1

To convert the equation Y-5 = 6(x+1) from point-slope form to slope-intercept form, isolate the variable Y on one side of the equation. First, distribute the 6 to both terms inside the parentheses. Next, add 5 to both sides of the equation. The equation written in slope-intercept form is y = 6x + 11.

Step-by-step explanation:

To convert the equation \(Y-5 = 6(x+1)\) from point-slope form to slope-intercept form, we need to isolate the variable \(Y\) on one side of the equation and express it in terms of \(x\). First, distribute the \(6\) to both terms inside the parentheses:

\(Y-5 = 6x + 6\)

Next, add \(5\) to both sides of the equation to isolate \(Y\):

\(Y = 6x + 11\)

The equation written in slope-intercept form is therefore y = 6x + 11.