Without additional context, we cannot determine the probability of picking one bag containing a toy and one containing money. If assuming only two distinct bags are available, the probability would be certain, 1.0. However, using the reference information on mutually exclusive and independent events, we can calculate specific probabilities for those scenarios.
To determine the probability that one bag contains a toy and one bag contains money when picked at random, one would need additional details such as the total number of bags, the number of bags containing toys, and the number of bags containing money. Assuming there are only two bags, one with a toy and one with money, and we are picking both bags, the probability would be 1.0, since it is certain you would pick one bag with a toy and one with money. However, this scenario is not specified in the provided information, thus we cannot give a definitive answer without further context.
Utilizing the reference information: If events H and D are mutually exclusive, and P(H) = 0.25 and P(D) = 0.15, then P(HD) represents the probability of both events happening at the same time. Since they are mutually exclusive, they cannot occur simultaneously, so the probability P(HD) is 0.0 (Option B). When two events are mutually exclusive, their intersection (happening together) is impossible.
In the context of independent events like A and B with probabilities P(A) = 0.2 and P(B) = 0.3, the probability of both A and B occurring, P(A AND B), is found by multiplying their individual probabilities: P(A) × P(B) = 0.2 × 0.3 = 0.06 (Option D).