Question

An open pipe on an organ creates

a fundamental frequency at
10500 Hz. How long is the pipe?

Answer 1

0.0163

Step-by-step explanation:

acellus

Answer 2

L = 1.61 cm

Step-by-step explanation:

The frequency of open organ pipe is given by :

`f=(nv)/(2L)`

Where

n = 1 for fundamental frequency

f = 10500 Hz

L is the length of the pipe

v is the speed of sound, v = 340 m/s

So,

`L=(nv)/(2f)\\\\L=(1* 340)/(2* 10500 )\\\\L=0.0161\ m\\\\or\\\\L=1.61\ cm`

So, the length of the pipe is 1.61 cm.