Question

Given t(x) =− 4.9t^ + 3t + 10,
* What is the value of t(1)?

Answer 1

The value of t(1) is 8.1.

Step-by-step explanation:

The question asks us to find the value of t(1) when given the function t(x) = − 4.9t^2 + 3t + 10. To evaluate t(1), we simply substitute '1' for every occurrence of 't' in the equation and then solve.

t(1) = − 4.9(1)^2 + 3(1) + 10

t(1) = − 4.9 + 3 + 10

t(1) = − 4.9 + 13

t(1) = 8.1

Therefore, the value of t(1) is 8.1.