Question

What is the ∆T given the heat loss for a system with qsystem = -1834.3J and a mZn = 34.8g (cZn = 0.390J/goC)?

a) -4.71°C
b) -7.89°C
c) -9.34°C
d) -11.23°C

Answer 1

The change in temperature (∆T) for the zinc system was calculated using the equation q = m × c × ∆T. After substituting the given values, the result obtained is approximately -135.22°C, which does not align with any of the given multiple choice options. There may be an error in the provided answer choices or data in the question.

Step-by-step explanation:

To calculate the change in temperature (∆T) for the zinc system, we need to use the equation q = m × c × ∆T, where q is the heat loss or gain, m is the mass, c is the specific heat capacity, and ∆T is the change in temperature.

Given that qsystem = -1834.3 J (heat loss, hence the negative sign), mZn = 34.8 g, and cZn = 0.390 J/g°C, we rearrange the equation to solve for ∆T: ∆T = q / (m × c).

Substituting the values we have: ∆T = (-1834.3 J) / (34.8 g × 0.390 J/g°C) = -1834.3 J / 13.572 J/°C ≈ -135.22°C. This result doesn't match with any of the provided options, suggesting a potential error in the provided answer choices or the question's data itself.