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When 50.0 mL of 0.100M iron (III) chloride is mixed with 50.0 mL of 0.100M lead (II) nitrate, why should we determine which reactant is limiting?

When 50.0 mL of 0.100M iron (III) chloride is mixed with 50.0 mL of 0.100M lead (II) nitrate, why should we determine which reactant is limiting?
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When 50.0 mL of 0.100M iron (III) chloride is mixed with 50.0 mL of 0.100M lead (II) nitrate, why should we determine which reactant

is limiting?

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User Andrew Rosenfeld
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1 Answer

8 votes
50.000.50.0050.00 I chloride mixed with 500 ml
answered
User Deumaudit
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7.8k points
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