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Write an equation of a line through the point (-3, -6) with a slope of -2/3

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Final answer:

To write an equation of a line through the point (-3, -6) with a slope of -2/3, you can use the point-slope form of a linear equation: y - y1 = m(x - x1).

Step-by-step explanation:

To write an equation of a line through the point (-3, -6) with a slope of -2/3, we can use the point-slope form of a linear equation, which is given by y - y1 = m(x - x1), where (x1, y1) is the given point and m is the slope. Substituting the values (-3, -6) and -2/3 into the equation, we get y - (-6) = -2/3(x - (-3)). Simplifying the equation gives y + 6 = -2/3(x + 3), which can be further simplified to y = -2/3x - 14/3.

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