Question

A speed camera takes two photographs of a car photo 2 was taken 0.5 seconds after photo 1 marks on the road are 0.8 meters apart calculate the average speed of the car in m/s

Answer 1

The car's average speed between the two photographs, taken 0.5 seconds apart, is 1.6 meters per second.

Step-by-step explanation:

The question involves calculating the average speed of a car based on two photographs taken by a speed camera, with marks on the road that are 0.8 meters apart. To calculate the speed, we use the formula:

Speed (v) = Distance (d) / Time (t)

If the two photographs were taken 0.5 seconds apart and the car traveled the distance of one mark on the road (0.8 meters) during this time, the calculation would be:

v = 0.8 m / 0.5 s = 1.6 m/s

Therefore, the car's average speed is 1.6 meters per second (m/s) between the two photographs.

Answer 2

The average speed of the car, between the two photographs, is 1.6 meters per second.

To calculate the average speed of the car based on the information provided, we need to know how many road marks (each 0.8 meters apart) the car passed between the two photographs.

However, since the exact number of marks is not specified, let's assume the car passed one mark in the 0.5 seconds between the two photographs.

Using the formula for average speed:

`\[ \text{Average Speed} = \frac{\text{Total Distance}}{\text{Total Time}} \]`

- Total Distance : If the car passed one mark, the distance traveled is 0.8 meters.

- Total Time : The time interval is 0.5 seconds.

Plugging these values into the formula:

`\[ \text{Average Speed} = \frac{0.8 \, \text{m}}{0.5 \, \text{s}} \]`

Let's calculate the average speed.

The average speed of the car, assuming it passed one mark (0.8 meters) in the 0.5 seconds between the two photographs, is 1.6 meters per second.