Question

A metal rod 0.50 m long moves with a speed of 2.0 m/s perpendicular to a magnetic field. If the induced emf between the ends of the rod is 0.75 V, what is the strength of the magnetic field?

Answer 1

The strength of the magnetic field in which a 0.5 m rod moves perpendicular with a speed of 2.0 m/s and induces an emf of 0.75 V is 0.75 T.

Step-by-step explanation:

The question is asking us to determine the strength of the magnetic field in which a metal rod is moving. The equation that relates the induced emf (Ε), the length of the rod (l), the velocity of the rod (v), and the magnetic field strength (B) is given by Faraday's Law of Induction, and in this case, can be expressed as Ε = B × l × v where the velocity is perpendicular to the magnetic field. Solving for B, we get B = Ε / (l × v). Using the given values, B = 0.75 V / (0.50 m × 2.0 m/s) = 0.75 V / 1.0 m²/s = 0.75 T.