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Francine wants to construct a pyramid using tempered glass She needs to construct the pyramid so that the height is 201 millimeters more than 2 times the base.

Letting b represent the base length and / the height of the pyramidconstruct an equation for the volume of the pyramid in terms of just the base length b.

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Final answer:

The volume of the pyramid Francine wants to construct, in terms of the base length b, is V = (2/3) × b³ + 67 × b², where the height is given as h = 2b + 201.

Step-by-step explanation:

Francine wants to construct a pyramid where the height (h) is 201 millimeters more than twice the base length (b). To write an equation for the volume of the pyramid in terms of the base length b, we first express the height h as h = 2b + 201.

The volume V of a pyramid is given by the formula V = (1/3) × base area × height. Since the base of the pyramid is a square with side length b, the area of the base is . Thus, substituting h into the volume formula and using for the base area, we get:

V = (1/3) × b² × (2b + 201)

Expanding this, we have:

V = (1/3) × b² × 2b + (1/3) × b² × 201

V = (2/3) × b³ + 67 × b²

Therefore, the equation for the volume of the pyramid in terms of the base length b is V = (2/3) × b³ + 67 × b².

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