Question

A straight 3.993 m wire carries a current of 0.380 A. If the wire is passed through a region of space with a uniform magnetic field of 0.803 T that is perpendicular to the flow of current, what is the magnitude of the force on the wire?

Answer 1

The magnitude of the force on the wire is 1.215 N.

Step-by-step explanation:

To calculate the magnitude of the force on the wire, we can use the formula:

F = I * L * B * sin(theta)

Where:

F is the force on the wire,

I is the current in the wire,

L is the length of the wire,

B is the magnitude of the magnetic field,

and theta is the angle between the direction of the current and the magnetic field.

In this case, we are given that:

I = 0.380 A,

L = 3.993 m,

B = 0.803 T,

and theta = 90 degrees (since the magnetic field is perpendicular to the flow of current).

Plugging in these values into the formula, we get:

F = 0.380 A * 3.993 m * 0.803 T * sin(90 degrees)

F = 1.215 N

Therefore, the magnitude of the force on the wire is 1.215 N.