Question

A straight 3.390 m wire carries a current of 0.408 A. If the wire is passed through a region of space with a uniform magnetic field of 0.723 T that makes an angle of 53.99 degrees to the flow of current, what is the magnitude of the force on the wire?

Answer 1

The magnitude of the force on a wire in a magnetic field can be calculated using the formula F = I * L * B * sin(θ), where F is the force, I is the current, L is the length of the wire, B is the magnetic field strength, and θ is the angle between the current and field direction.

Step-by-step explanation:

To calculate the magnitude of the force on a wire carrying a current in a magnetic field, you can use the formula F = I * L * B * sin(θ), where F is the force, I is the current, L is the length of the wire, B is the magnetic field strength, and θ is the angle between the direction of the current and the magnetic field. In this case, the wire carries a current (I) of 0.408 A, has a length (L) of 3.390 m, the magnetic field (B) is 0.723 T, and the angle (θ) is 53.99 degrees. Using the formula, the force is calculated as F = 0.408 A * 3.390 m * 0.723 T * sin(53.99 degrees). When we perform this calculation, keeping in mind that sin(53.99 degrees) is approximately 0.8, we can find out the magnitude of the magnetic force on the wire.