asked 144k views
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Tristan tried his luck with the lottery. He can win $60 if he can correctly choose the 3 numbers drawn. If order matters and there are 13 numbers in the drawing, how many different ways could the winning numbers be drawn? Your answer:

asked
User Sakir
by
8.7k points

1 Answer

4 votes

Final answer:

There are 1,716 different ways the winning numbers can be drawn.

Step-by-step explanation:

To determine the number of different ways the winning numbers can be drawn, we need to use the concept of permutations. In this case, the order matters, and there are 13 numbers to choose from for each of the three positions.

To calculate the number of permutations, we use the formula:

nPr = n! / (n - r)!

Where n is the total number of options (13 in this case) and r is the number of selections (3 in this case).

Using the formula, we have:

nPr = 13! / (13 - 3)! = 13! / 10! = 13 * 12 * 11 = 1,716

Therefore, there are 1,716 different ways the winning numbers can be drawn.

answered
User Johnny Everson
by
8.8k points
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