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Suppose the actual air pressure in each tire is a random variable X for the right tire and Y for the left tire, with joint pdf:

f(x, y) = {K(x^2 + y^2) for 20 ≤ x ≤ 30 and 20 ≤ y ≤ 30, otherwise.

a. What is the value of K?
b. What is the probability that both tires are underfilled?
c. What is the probability that the difference in air pressure between the two tires is at most 2 psi?
d. Determine the marginal distribution of air pressure in the right tire alone.
e. Are X and Y independent random variables?
f. Determine the conditional probability density function of Y given that X = x, and the conditional probability density function of X given that Y = y.
g. If the pressure in the right tire is found to be 22 psi, what is the probability that the left tire has a pressure of at least 25 psi? Compare this to P(Y ≥ 25).
h. If the pressure in the right tire is found to be 22 psi, what is the expected pressure in the left tire, and what is the standard deviation of pressure in this tire?

asked
User Pirulino
by
8.1k points

1 Answer

4 votes

Final answer:

The joint pdf problem requires finding a normalizing constant K, calculating various probabilities involving the pressure in both tires, determining independence, and calculating conditional distributions. Marginal and conditional distributions are also needed to find expected values and standard deviations.

Step-by-step explanation:

Joint Density Function and Properties

To answer the student's question, we first need to find the value of the normalization constant K for the joint pdf. Since the pdf must integrate to 1 over the region of interest, we can set up the integral for K:

\[1 = \int_{20}^{30} \int_{20}^{30} K(x^2 + y^2) \, dx \, dy\]

We solve this integral to find K.

For the probability that both tires are underfilled, we define 'underfilled' and integrate the joint pdf over that region.

The probability that the difference in air pressure is at most 2 psi involves setting up and evaluating an appropriate integral with the given constraint.

The marginal distribution of X is found by integrating the joint pdf over all values of Y.

Independence of X and Y can be determined by seeing if the product of their marginal distributions equals the joint distribution.

Conditional probability density functions are found by dividing the joint pdf by the marginal pdf of the variable we are conditioning on.

Finally, the questions related to the pressure being 22 psi in the right tire involve using the conditional distribution of Y given X = 22.

The mean and standard deviation of the left tire pressure, given the pressure in the right tire, requires calculating expected value and variance using the conditional pdf.

answered
User Lanting Guo
by
8.1k points
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