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What is the probability of first drawing the ace of spades and

then drawing any of the three remaining aces from a 52-card
pack?

1 Answer

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Final answer:

The probability of first drawing the ace of spades and then drawing any of the three remaining aces from a 52-card deck is 1/884.

Step-by-step explanation:

The probability of first drawing the ace of spades and then drawing any of the three remaining aces from a 52-card deck can be calculated as follows:

  1. There are 4 aces in a deck, so the probability of drawing the ace of spades is 1/52.
  2. After the first ace is drawn, there are 51 cards remaining, of which 3 are aces. So the probability of drawing any of the three remaining aces is 3/51.
  3. To find the probability of both events occurring, we multiply the individual probabilities. Therefore, the probability of first drawing the ace of spades and then drawing any of the three remaining aces is (1/52) * (3/51) = 1/884.

Therefore, the probability of first drawing the ace of spades and then drawing any of the three remaining aces from a 52-card deck is 1/884.

answered
User Akshar Patel
by
8.0k points
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