Question

The mean daily production of a herd of cows is assumed to be normally distributed with a mean of 33 liters and standard deviation of 5.6 liters.

what is the probability that daily production is less than 35.2 liters? Use technology to get your probability.

Answer 1

To find the probability that the daily production is less than 35.2 liters, use the standard normal distribution and calculate the z-score.

Step-by-step explanation:

To find the probability that the daily production is less than 35.2 liters, we can use the standard normal distribution. Step 1: Calculate the z-score using the formula z = (x - mean) / standard deviation. Step 2: Look up the z-score in the standard normal distribution table or use technology to find the corresponding probability. In this case, the z-score is (35.2 - 33) / 5.6 = 0.4286. The probability can be found by looking up the z-score or using technology, which in this case is approximately 0.6659 or 66.59%.