Question

If A and B are mutually exclusive events such that P(A = 0.35 and P(B=0.45, find
(i) P(A∪B)

Answer 1

The probability of A or B occurring is 0.80.

Step-by-step explanation:

For mutually exclusive events A and B, the probability (P) that at least one occurs (A or B) is (PA + PB). In this case, we know that PA = 0.35 and PB = 0.45. Therefore, P(A∪B) = PA + PB = 0.35 + 0.45 = 0.80.