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The length of a rectangle is 7 cm more than twice the width. The perimeter is 86 cm. Find

the dimensions of the rectangle.

asked
User Chaami
by
8.3k points

1 Answer

4 votes

Final answer:

The width of the rectangle is 12 cm and the length is 31 cm.

Step-by-step explanation:

Let's represent the width of the rectangle as w. According to the problem, the length of the rectangle is 7 cm more than twice the width, so we can express the length as 2w + 7. The formula for the perimeter of a rectangle is P = 2(l + w), where l is the length and w is the width. In this case, the perimeter is given as 86 cm. Plugging in the values into the formula, we get:

86 = 2((2w + 7) + w)

Simplifying the equation:

86 = 2(3w + 7)

86 = 6w + 14

72 = 6w

w = 12

Substituting the value of w back into the expression for the length:

l = 2w + 7 = 2(12) + 7 = 31

Therefore, the dimensions of the rectangle are 12 cm by 31 cm.

answered
User Rafaelc
by
8.5k points

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