asked 162k views
2 votes
The galvanometer from problem 1 (reads from −300Ato +300Awith an internal resistance of 100Ω)is to be used to create an ammeter to read a maximum current of 5A.Sketch the design of the ammeter being used to measure the current through a resistor .

asked
User SomeoneS
by
7.3k points

1 Answer

5 votes

Final answer:

To design an ammeter using a galvanometer to measure a maximum current of 5A, you need to connect it in parallel with a shunt resistance. Use the formula Rs = (Rg / Imax) - Rg to calculate the required shunt resistance.

Step-by-step explanation:

A galvanometer can be used as an ammeter by placing it in parallel with a small resistance, called the shunt resistance. The shunt resistance allows most of the current to pass through it, allowing the ammeter to measure currents greater than those producing a full-scale deflection of the galvanometer.

In this case, to design an ammeter to measure a maximum current of 5A, you would need to connect the galvanometer in parallel with a shunt resistance that can handle the current. The shunt resistance can be calculated using the formula:

Rs = (Rg / Imax) - Rg

Where Rg is the internal resistance of the galvanometer and Imax is the maximum current. Substitute the given values to determine the required shunt resistance.

answered
User Ohnoplus
by
8.6k points