Question

Two conducting plates are 2 cm apart. Potentials of plates are

+350 V and -150 V. Find the electric force acting on particle
between the plates when the particle has the charge +2,5 C.

Answer 1

4.20

Step-by-step explanation:

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Answer 2

The electric force between the plates can be determined using Coulomb's law and the formula for electric field strength. Plugging in the given values, the force is calculated to be 312.5 N.

Step-by-step explanation:

The electric force experienced by a charged particle between two conducting plates can be determined using Coulomb's law and the formula for electric field strength. The electric field strength between the plates is given by the equation:

E = (V2 - V1) / d

where E is the electric field strength, V2 is the potential of the positively charged plate, V1 is the potential of the negatively charged plate, and d is the distance between the plates. To find the electric force on the particle, we can use the equation:

F = qE

where F is the electric force, q is the charge of the particle, and E is the electric field strength. Plugging in the values provided:

E = (350 V - (-150 V)) / 2 cm = 250 V / 2 cm = 125 V/cm = 125 N/C

F = (2.5 C)(125 N/C) = 312.5 N

Therefore, the electric force acting on the particle between the plates is 312.5 N.