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If you need to make 3000L of a 5.00% solution of sodium chloride, how much sodium chloride do we need?.

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Final answer:

To make a 3000L of 5.00% sodium chloride solution, you would need 150,000g of NaCl. This is calculated using the mass percentage formula and assuming the density of the solution is similar to water.

Step-by-step explanation:

To calculate the mass of sodium chloride required for making a 3000L of a 5.00% sodium chloride solution, you need to know the mass percentage formula:

mass of the solute (NaCl) = (% concentration) × (total mass of the solution)

Assuming that the density of the solution is similar to that of water, which is approximately 1 g/mL, you can convert 3000L to grams, as there are 1000g in 1L:

3000L × 1000g/L = 3000000g of solution

Now, you can use the given 5.00% concentration to find out the mass of NaCl:

(5.00/100) × 3000000g = 150,000g of NaCl

This means you would need to weigh out 150,000g of NaCl and combine it with water to get the desired concentration of sodium chloride solution.

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