asked 50.5k views
2 votes
A wavelength of 640nm what is the energy of photon begin emitted

asked
User Toohool
by
8.2k points

1 Answer

4 votes

Final answer:

The energy of a photon can be calculated using the equation E = hc/λ, where E is the energy of the photon, h is Planck's constant, c is the speed of light, and λ is the wavelength of the photon. Plugging in the given values, the energy of the photon is 3.09 × 10-19 J.

Step-by-step explanation:

The energy of a photon can be calculated using the equation:

E = hc/λ

Where:

  • E is the energy of the photon
  • h is Planck's constant (6.626 × 10-34 J·s)
  • c is the speed of light (3.00 × 108 m/s)
  • λ is the wavelength of the photon (in meters)

In this case, the wavelength of the photon is given as 640 nm (or 640 × 10-9 m). Plugging this value into the equation:

E = (6.626 × 10-34 J·s) × (3.00 × 108 m/s) / (640 × 10-9 m)

Simplifying the expression:

E = 3.09 × 10-19 J

Therefore, the energy of the photon being emitted is 3.09 × 10-19 J.

answered
User Larz
by
8.4k points

Related questions

1 answer
5 votes
6.5k views
Welcome to Qamnty — a place to ask, share, and grow together. Join our community and get real answers from real people.