Final answer:
Using Boyle's Law, the volume of air inside a balloon when pressure increases from 0.810 atm to 0.910 atm decreases from 15.0 L to approximately 13.4 L due to the inverse relationship between pressure and volume.
Step-by-step explanation:
The question you've asked involves the application of Boyle's Law in chemistry, which states that the pressure and volume of a gas have an inverse relationship, when temperature is held constant. To find the new volume of the air inside the balloon when the pressure is increased to 0.910 atm from 0.810 atm, we can use Boyle's Law equation:
P1 × V1 = P2 × V2
Inserting the given values:
0.810 atm × 15.0 L = 0.910 atm × V2
Now, we solve for V2:
V2 = (0.810 atm × 15.0 L) / 0.910 atm
V2 = 13.4 L (approximately)
This tells us that when the pressure on the balloon is increased, the volume decreases to maintain the pressure-volume product. The volume of the air inside the balloon under a pressure of 0.910 atm will be approximately 13.4 liters.