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Perimeter of 52 ft & width of 12 ft

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Using the formula for the perimeter of a rectangle (P = 2l + 2w), given a perimeter of 52 ft and a width of 12 ft, the length is calculated to be 14 ft.

If a student is given the perimeter of a rectangle as 52 ft and the width as 12 ft, they want to find the length of the rectangle. To do this, they would use the formula for the perimeter of a rectangle, which is P = 2l + 2w, where P is the perimeter, l is the length, and w is the width. In this case, we already have the perimeter (P=52 ft) and the width (w=12 ft).

To find the length, we rearrange the formula to solve for l:
52 = 2l + 2(12)
52 = 2l + 24
52 - 24 = 2l
28 = 2l
14 = l

So the length of the rectangle is 14 ft.

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User Chuan Ma
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