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(4k^2– 12) – (6k^2– 3k – 10)

(4k^2– 12) – (6k^2– 3k – 10)
asked 32.6k views
22 votes
(4k^2– 12) – (6k^2– 3k – 10)

asked
User Evgeny Kuznetsov
by
8.5k points

1 Answer

14 votes

Answer:

-2k^2+3k-2

Explanation:

(4k^2– 12) – (6k^2– 3k – 10)

Expanding using distributive prop.

4k^2-12-6k^2+3k+10

-2k^2+3k-2

answered
User Carles
by
8.2k points
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