Question

suppose of zinc iodide is dissolved in of a aqueous solution of potassium carbonate.calculate the final molarity of iodide anion in the solution. you can assume the volume of the solution doesn't change when the zinc iodide is dissolved in it.be sure your answer has the correct number of significant digits.

Answer 1

The final molarity of iodide anion in the solution is 0.241 M.

The final molarity of iodide anion in the solution, we need to first calculate the moles of iodide anions in the solution.

Step 1: Calculate the moles of zinc iodide dissolved in the solution.

13.5 g ZnI2 * (1 mol ZnI2 / 319.85 g ZnI2) = 0.0421 mol ZnI2

Step 2: Calculate the moles of iodide anions in the solution.

1 mol ZnI2 contains 2 mol I-

0.0421 mol ZnI2 * 2 mol I- / 1 mol ZnI2 = 0.0842 mol I-

Step 3: Calculate the final molarity of iodide anion in the solution.

0.0842 mol I- / 0.350 L = 0.241 M I .