asked 46.9k views
23 votes
A rocket is launched from a tower. The height of the rocket, y in feet, is related to the

time after launch, x in seconds, by the given equation. Using this equation, find the
maximum height reached by the rocket, to the nearest tenth of a foot.
y = -16x2 + 160x + 51

asked
User RFV
by
7.8k points

1 Answer

10 votes

Answer:

451

Explanation:

on a calculator go to y= and type the equation in and then go to the table.

answered
User Davis
by
8.4k points
Welcome to Qamnty — a place to ask, share, and grow together. Join our community and get real answers from real people.