Question

jim wishes to push a 100. n wood crate across a wood floor. what is the minimum horizontal force that would be required to start the crate moving? (coefficient of kinetic friction

Answer 1

The minimum horizontal force that would be required to start the crate moving is 50N.

The greatest force of static friction acting between the crate and the floor must match the minimum horizontal force needed to start the crate moving.

The following calculates the maximum static friction force:

`F_(f)` = μN

Whereas

μ is the static friction coefficient?

N is the typical response that the crate receives from the floor.

The highest coefficient of static friction for wood-wood, as in this instance, is about μ = 0.5.

The normal reaction for a horizontal surface is equal to the object's weight in this instance N=100 N.

Thus, the following will be the minimal horizontal force needed:

F=
`F_(f)`=μN= (0.5) ( 100N )= 50N