Question

What is the equation of a line that passes through the point (-2,140) and is perpendicular to the line with the following equation y= -2/5x - 1?

a) y = 5/2x + 135
b) y = 5/2x - 136
c) y = 2/5x + 140
d) y = -5/2x + 139

Answer 1

To find the equation of a line that is perpendicular to another line, we need to find the negative reciprocal of the slope of the given line. The equation of the line that passes through the point (-2, 140) and is perpendicular to the line y = -2/5x - 1 is y = 5/2x + 135. Hence, option a) is correct.

Step-by-step explanation:

To find the equation of a line that is perpendicular to another line, we need to find the negative reciprocal of the slope of the given line.

The given line has a slope of -2/5, so the negative reciprocal would be 5/2. Therefore, the slope of the perpendicular line is 5/2.

Using the point-slope form of a linear equation, we can plug in the values of the slope and the given point (-2, 140) to find the equation of the perpendicular line. The equation of the line is y = 5/2x + 135, so the answer is option a) y = 5/2x + 135.