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Write the equation of the line perpendicular to y=8x 13 with a y-intercept at (0,10)

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Final answer:

The equation of the line perpendicular to y=8x+13 with a y-intercept at (0,10) is y = (-1/8)x + 10.

Step-by-step explanation:

To find the equation of the line perpendicular to y = 8x + 13 with a y-intercept at (0,10), we need to determine the slope of the original line and then find the negative reciprocal of that slope to get the slope of the perpendicular line. The original line has a slope of 8, so the perpendicular line will have a slope of -1/8. Using the slope-intercept form of a line y = mx + b, where m is the slope and b is the y-intercept, we can substitute the values into the equation to find the equation of the perpendicular line: y = (-1/8)x + 10.

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User Alexander Craggs
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