Question

Tauri is 49 years old. angeline is 28 years old. how many years ago was tauri's age 4 times angeline's age?

Answer 1

The problem is solved by setting a variable x for the number of years ago when Tauri's age was four times Angeline's. Solving the equation results in x being 21, which means that 21 years ago, Tauri was four times as old as Angeline.

Step-by-step explanation:

To solve this problem, we need to determine when Tauri's age was four times that of Angeline's age. We'll let x represent the number of years ago when this condition was true. Currently, Tauri is 49 years old and Angeline is 28 years old.

We'll set up an equation to reflect the situation x years ago:

49 - x = 4 * (28 - x)

Solving the equation:

1. 49 - x = 112 - 4x
2. 49 - 112 = -4x + x
3. -63 = -3x
4. x = 21

So, 21 years ago, Tauri's age was four times that of Angeline's age.