Question

The ionic compound, (nh4)2so4, will fully dissolve in water. if 10.86 g is dissolved in water to give a final volume of 529.0 ml, then find the following ion concentrations?

Answer 1

The ion concentrations in the (NH4)2SO4 solution are approximately 0.31 M for NH4+ and 0.31 M for SO42-.

Step-by-step explanation:

To find the ion concentrations in the solution of (NH4)2SO4, we need to determine the number of moles of (NH4)2SO4 dissolved in the given volume of water. The molar mass of (NH4)2SO4 is 132.14 g/mol, so 10.86 g is equal to 0.0822 moles. Dividing this by the final volume of the solution in liters (529.0 mL = 0.529 L) gives us a concentration of (NH4)2SO4 of approximately 0.155 M.

Since (NH4)2SO4 dissociates into 2 NH4+ ions and 1 SO42- ion, the concentrations of NH4+ and SO42- are twice the concentration of (NH4)2SO4. Therefore, the concentration of NH4+ is approximately 0.31 M, and the concentration of SO42- is also approximately 0.31 M.